egghelp/eggheads community

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2003-04-15T10:35:28-04:00

thanks!

now all works fine!

Statistics: Posted by eiSi — Tue Apr 15, 2003 10:35 am

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2003-04-15T08:39:50-04:00

It should be neither.

You are using a bind type of MSGM. This means private messages sent to the bot.

In your script, you are using "nick uh hand chan arg".

There is no channel in a private message.

Statistics: Posted by ppslim — Tue Apr 15, 2003 8:39 am

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2003-04-15T08:37:01-04:00

-error- didnt watch correct....where's the delete post button ?

Statistics: Posted by GodOfSuicide — Tue Apr 15, 2003 8:37 am

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2003-04-15T06:17:53-04:00

all right! I'll try it asap!

update:

it says:

|12:28| »» [Rbot] [12:28] Tcl error [handlemsg]: wrong # args: should be "handlemsg nick uhost hand chan arg"

and the code:

Code:

bind msgm - * handlemsgproc handlemsg {nick uhost hand chan arg} {global isO currLine homeif {$nick != "O"} {return} else {set response [split $arg " "]if {[lindex $response 0] != "Pos"} {return} else {msg $home "debug"incr currLineif {$currLine < 6} {foreach i [split $misc2 ""] {notice "tuxX" "test"}} else {return}}}}

any suggestions?

thanks again!

Statistics: Posted by eiSi — Tue Apr 15, 2003 6:17 am

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2003-04-15T04:15:18-04:00

THat will teach me to make assumptions.

Your error is likely your use of the $args variable.

Args has a special meaning when used in a Tcl procedure definition.

Where each other variable will contain a string of text, for that portion passed, args contains a list of arguments.

This allows you to create unlimited length variable lists, without having to specificaly delare them.

As $args is allready a list, there is no need to split it. Aditionaly, the split command with split using " " by default (so iliminating this part of the command will save trouble).

Spliting a list causes all sorts of problems, leaving junk characters from the original list, when obtaining an index.

The quickest method of resolving this, is to use arg rather than args. The split command can remain (including the " " if so wanted), and then all should work.

Statistics: Posted by ppslim — Tue Apr 15, 2003 4:15 am

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2003-04-15T02:28:01-04:00

okay!

thanks again!

@ppslim: I don't think so, because I tried to put the debug think just right at the beginning, there it works...

Statistics: Posted by eiSi — Tue Apr 15, 2003 2:28 am

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2003-04-14T09:22:42-04:00

It may be that another script it overwritting the msg proc.

Try creating a unique name for it, and use it in your scripts to make sure this isn't the problem.

Statistics: Posted by ppslim — Mon Apr 14, 2003 9:22 am

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2003-04-14T09:19:50-04:00

If you use this "msg" in more than one proc or somethinglike this and you don't want to have to many lines, yes, but this will slow it down a bit, because he calls another proc while is in one, after he finishes it he returns to it's original one and continues with it till the end of it.

Statistics: Posted by caesar — Mon Apr 14, 2003 9:19 am

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2003-04-14T09:06:03-04:00

thx, but the msg proc looks like this:

Code:

proc msg {a b} {putserv "privmsg $a :$b"}

and if I place the debug thing after the first else bracket, it works fine.

could it be a problem of speed?

Statistics: Posted by eiSi — Mon Apr 14, 2003 9:06 am

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2003-04-14T02:45:41-04:00

Replace from:

Code:

msg $home "debug"

to:

Code:

putserv "PRIVMSG $home :debug"

and you will see an debug thing, or try the putlog as stdragon sugested you.

Statistics: Posted by caesar — Mon Apr 14, 2003 2:45 am

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2003-04-13T22:33:33-04:00

Where is the 'msg' proc defined? Try replacing msg with putlog, and just watch on the partyline for it to appear.

putlog "debug"

Statistics: Posted by stdragon — Sun Apr 13, 2003 10:33 pm

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2003-04-10T09:14:36-04:00

ok, getting more conrete:

|03:12| »» [Rbot] Msg to o: chanoplist #rtest
|03:12| »» [Rbot] [15:12] [O!operserv@operservice.mynet.org] Pos Score User/Last seen
|03:12| »» [Rbot] [15:12] [O!operserv@operservice.mynet.org] 1 1 tuxx tuxx@myhost.de tuxx
|03:12| »» [Rbot] [15:12] [O!operserv@operservice.mynet.org] 2 1 Last seen: Thu Apr 10 01:04:12 2003
|03:12| »» [Rbot] [15:12] [O!operserv@operservice.mynet.org] 3 1 Last seen: Thu Apr 10 01:04:12 2003
|03:12| »» [Rbot] [15:12] [O!operserv@operservice.mynet.org] 4 1 @rbot Rbot@myhost.de
|03:12| »» [Rbot] [15:12] [O!operserv@operservice.mynet.org] --- End of list - 4 listed ---

so, my current proc is like this:

Code:

bind msgm - * handlemsgset isO 0set currLine 0set home "#mychan"proc handlemsg {nick uhost hand chan args} {global isO currLine homeif {$nick != "O"} {return} else {set response [split $args " "]if {[lindex $response 0] != "Pos"} {return} else {msg $home "debug"incr currLineif {$currLine < 6} {foreach i [split $misc2 ""] {notice "tuxX" "test"}} else {return}}}}

It should send "debug" to the channel, but it doesn't. any suggestions?

thanks!

Statistics: Posted by eiSi — Thu Apr 10, 2003 9:14 am

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2003-04-09T02:30:13-04:00

thanks a lot!

this really helps me!

I'll try it today!

Statistics: Posted by eiSi — Wed Apr 09, 2003 2:30 am

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2003-04-08T16:52:23-04:00

Use a msgm bind on *. Make sure the nick is "blubb". If the text says "Pos nick desc", set a flag to 1. Otherwise, make sure flag is 1 already (if not, return). Split the text, make sure the first item on the line is a number from 1-6. Check to see if the second item is @rwer. If it is, success! If the first item on the line is > 6, and flag is 1, then failure, and set flag to 0.

There's your logic, now you're 3/4 done!

Statistics: Posted by stdragon — Tue Apr 08, 2003 4:52 pm

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2003-04-08T08:20:12-04:00

hi there!

a little question:

I message a channelservice:

msg blubb showmedatop5

and it returns:

Pos nick desc
1 @blub blubb0r
2 @asd asdasdasd
3 @asdasdasd adsdsasdasad
4 @adddd dddddd
5 @rwer werwerwer
6 @mmm mmmm

how to "check" if the the user rwer is in the first 5/6 returned lines?

can you please help me with this problem? thanks a lot!

Statistics: Posted by eiSi — Tue Apr 08, 2003 8:20 am