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expr ALWAYS with double?

2003-02-22T07:12:08-04:00

You must have put parenthesis around the integer part. Expr follows order of operations. All you have to do is:

puthelp "PRIVMSG $chan :[expr 1.0 * $arg]"

You could also do a regsub which adds a .0 to all integers in the expression.

But if you are using $arg as input from a user, be careful, because expr will evaluate commands in brackets.

e.g.
% set arg {3 + [hello]}
3 + [hello]
% expr $arg
invalid command name "hello"

Statistics: Posted by stdragon — Sat Feb 22, 2003 7:12 am

expr ALWAYS with double?

2003-02-22T06:47:10-04:00

Code:

puthelp "PRIVMSG $chan :[expr (1.0 * ($arg))]"

"= 3/2":
it just puts "1.0"...

but doesnt really matter. was just a test.

Statistics: Posted by arcane — Sat Feb 22, 2003 6:47 am

expr ALWAYS with double?

2003-02-21T15:17:20-04:00

Just put "1.0 *' at the beginning of the expr and it'll always be double.

% expr "1.0 * 3/2"
1.5

Statistics: Posted by stdragon — Fri Feb 21, 2003 3:17 pm

expr ALWAYS with double?

2003-02-21T12:38:16-04:00

It should type:"3 / 2"

Statistics: Posted by caesar — Fri Feb 21, 2003 12:38 pm

expr ALWAYS with double?

2003-02-21T11:42:33-04:00

yes you do

Statistics: Posted by Papillon — Fri Feb 21, 2003 11:42 am

expr ALWAYS with double?

2003-02-21T11:38:21-04:00

hi
ive got this simple script

Code:

bind pub - "=" calc_calcproc calc_calc {nick userhost hand chan arg} {puthelp "PRIVMSG $chan :[expr $arg]"}

but if a user types "= 3/2", the result is "1" because expr calculates integers. how can i tell expr to ALWAYS use doubles? result should be "1.5". ill have to change $arg, havent i?

Statistics: Posted by arcane — Fri Feb 21, 2003 11:38 am