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set $var with $arg ...

2007-11-04T12:51:20-04:00

Just for your information i just got it !

REPLACE:

Code:

#HERE IS MY PROBLEM !!!!!! set set_rules $[string tolower [lindex $arg 0]]_rules #END OF PROBLEM

BY:

Code:

#NO MORE PROBLEM !!!!!! set set_rules [string tolower [lindex $arg 0]]_rulesset set_rules [set $set_rules]#END

Enjoy !

Statistics: Posted by wubmerlin — Sun Nov 04, 2007 12:51 pm

set $var with $arg ...

2007-11-04T12:20:42-04:00

I think that you can have a solution with eval or subst, but I can't give you the correct syntax you need.
Peharps anyone else?

Statistics: Posted by CrazyCat — Sun Nov 04, 2007 12:20 pm

set $var with $arg ...

2007-11-04T11:57:54-04:00

Hello i wan tto know if this is possible

Code:

bind pub - !rules pub_rulesset public_rules "test public"set private_rules "test private"set pm_rules "test pm"proc pub_rules { nick uhost hand chan arg } {global public_rules pm_rules private_rulesif {[string tolower [lindex $arg 0]] != ""} {#HERE IS MY PROBLEM !!!!!!set set_rules $[string tolower [lindex $arg 0]]_rules#END OF PROBLEMputhelp "PRIVMSG $chan :[string toupper [lindex $arg 0]] Rules"puthelp "PRIVMSG $chan :$set_rules"}

I want to grabmy var with the arg, example if i type !rules public

$arg = public
i want to set:
set set_rules $$arg
Like this : set set_rules $public_rules

And i dont want set it with if $arg == public ... i want it like this b/c i have 250 rules to set and i want to clean my code ( already done with the IF )

Thanks alot !

Statistics: Posted by wubmerlin — Sun Nov 04, 2007 11:57 am